Question

time t(s) plane position (video) model for position s(t) = 1/2 1.7t² model for velocity v(t) = 1.7t model for acceleration a(t) = 1.7
0s 0m
7.4 50m
10.7 100m
13.3 150m
15.6 200m
17.3 250m
19.0 300m
20.4 350m
21.8 400m
23.1 450m
24.3 500m
motion
describe this motion:

Explanation:

The position - time graph shows a non - linear increase in the position of the plane over time. The model for position $s(t)=\frac{1}{2}\times1.7t^{2}$ indicates a uniformly accelerated motion as it follows the kinematic equation $s = s_0+v_0t+\frac{1}{2}at^{2}$ with initial position $s_0 = 0$ and initial velocity $v_0 = 0$ and acceleration $a = 1.7\ m/s^{2}$. The velocity - time relationship $v(t)=1.7t$ also shows a linear increase in velocity over time consistent with a constant acceleration, and the constant acceleration $a(t)=1.7\ m/s^{2}$ further confirms this.

Answer:

The plane is undergoing uniformly accelerated motion with an acceleration of $1.7\ m/s^{2}$, starting from rest at the origin.