Question

three pumps are pumping fluid at constant rates. for each, the amount of fluid pumped depends on time, as shown below. pump a: a graph with time (h) on the x - axis (0,1,2,3,4) and amount of fluid (l) on the y - axis (40,80,120,160,200,240,280,320). a line passes through (0,0) and other points. pump b: a table with time (hours) (0,1,2,3) and amount of fluid (liters) (0,90,180,270). pump c: the formula f = 70t, where f is the amount of fluid in liters and t is the time in hours.

Explanation:

Step1: Find rate of Pump A

From the graph, when \( t = 2 \) hours, amount is \( 200 \) L. Rate \( r_A=\frac{200}{2}=100 \) L/h.

Step2: Find rate of Pump B

From the table, in 1 hour, amount is 90 L. Rate \( r_B = 90 \) L/h.

Step3: Find rate of Pump C

From the formula \( f = 70t \), rate \( r_C=70 \) L/h.

Step4: Compare rates

\( 100>90>70 \), so Pump A has the fastest rate.

Answer:

Pump A