QUESTION IMAGE
Question
these triangles are similar.
solve for x.
\\(x = \\)
Identify corresponding sides using angle markers
Using the Similar Triangles knowledge point
- In the larger triangle, the side of length \(30\) is adjacent to the angles \(41^\circ\) and \(56^\circ\).
- In the smaller triangle, the side of length \(12\) is adjacent to the angles \(41^\circ\) and \(56^\circ\).
- Therefore, the side of length \(30\) corresponds to the side of length \(12\).
Match the remaining corresponding sides
Using the Similar Triangles knowledge point
- In the larger triangle, the side of length \(20\) is adjacent to the angle \(56^\circ\) and the unmarked angle.
- In the smaller triangle, the side of length \(x\) is adjacent to the angle \(56^\circ\) and the unmarked angle.
- Therefore, the side of length \(20\) corresponds to the side of length \(x\).
Set up and solve the proportion
Using the Corresponding Sides Ratio knowledge point
$$
\frac{x}{20} = \frac{12}{30}
$$
$$
x = 20 \cdot \frac{12}{30} = 20 \cdot \frac{2}{5} = 8
$$
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These triangles are similar. Solve for x.
\(x =\) <blank>8</blank>