Question

1. there are electrons, protons, and neutrons in an atom of 115in2+.

Explanation:

Step1: Determine the number of protons

The atomic number of Indium (In) is \(49\). For any atom or ion, the number of protons is equal to the atomic number. So, the number of protons \(p = 49\).

Step2: Determine the number of electrons

For a neutral atom, the number of electrons \(e\) is equal to the number of protons. But for the ion \(^{115}\text{In}^{2 +}\), it has lost \(2\) electrons. So, the number of electrons \(e=49 - 2=47\).

Step3: Determine the number of neutrons

The mass number \(A = 115\). The formula for the number of neutrons \(n\) is \(n=A - p\). Substituting \(A = 115\) and \(p = 49\), we get \(n=115 - 49 = 66\).

Answer:

\(47\) electrons, \(49\) protons, and \(66\) neutrons.