Question

there is a combined figure (a rectangle and a triangle) with dimensions: rectangle has length 3 ft and height 1.5 ft; triangle has base - related dimensions 4.5 ft, 3 ft, and height 3 ft. the formula given is \\(\left( \frac{4.5 \times 3}{2} \
ight) + 3 \times 1.5\\), and we need to find the area in \\(\square\\) ft².

Explanation:

Step1: Calculate the area of the triangle

The formula for the area of a triangle is $\frac{base \times height}{2}$. Here, base is 4.5 ft and height is 3 ft. So, $\frac{4.5 \times 3}{2} = \frac{13.5}{2} = 6.75$ square feet.

Step2: Calculate the area of the rectangle

The formula for the area of a rectangle is $length \times width$. Here, length is 3 ft and width is 1.5 ft. So, $3 \times 1.5 = 4.5$ square feet.

Step3: Sum the two areas

Add the area of the triangle and the area of the rectangle: $6.75 + 4.5 = 11.25$ square feet.

Answer:

11.25