Question

a tank whose bottom is a mirror is filled with water to a depth of 19.2 cm. a small fish floats motionless 8.00 cm under the surface of the water.
part a
what is the apparent depth of the fish when viewed at normal incidence to the water?
express your answer in centimeters. use 1.33 for the index of refraction of water.
view available hint(s)
submit
part b
what is the apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence?

Explanation:

Step1: Recall apparent depth formula

The formula for apparent depth \( d_{apparent} \) when an object is in a medium with refractive index \( n \) and real depth \( d_{real} \) is \( d_{apparent}=\frac{d_{real}}{n} \).

Step2: Identify values

Here, the real depth of the fish (distance from water surface) \( d_{real} = 8.00\space cm \), and refractive index of water \( n = 1.33 \).

Step3: Calculate apparent depth

Substitute the values into the formula: \( d_{apparent}=\frac{8.00}{1.33}\approx6.02\space cm \).

Answer:

\( 6.02 \)