Question

the table shows the rainfall for three days in april.
the first row shows the total number of inches of rain.
the second row shows the total number of hours during which the rain fell.

date	april 11	april 12	april 13
total time (hours)	4	6	3

the day with the least amount of rainfall per hour is
the day with the greatest amount of rainfall per hour is
options: april 11, april 12, april 13

Explanation:

Step1: Calculate rainfall per hour for April 11

Rainfall per hour = Rainfall (inches) / Total Time (hours) = $\frac{5}{8} \div 4 = \frac{5}{8} \times \frac{1}{4} = \frac{5}{32}$ inches per hour.

Step2: Calculate rainfall per hour for April 12

Rainfall per hour = $\frac{7}{8} \div 6 = \frac{7}{8} \times \frac{1}{6} = \frac{7}{48}$ inches per hour.

Step3: Calculate rainfall per hour for April 13

Rainfall per hour = $\frac{5}{16} \div 3 = \frac{5}{16} \times \frac{1}{3} = \frac{5}{48}$ inches per hour.

Step4: Compare the three values

Convert to common denominator (96):

• $\frac{5}{32} = \frac{15}{96}$
• $\frac{7}{48} = \frac{14}{96}$
• $\frac{5}{48} = \frac{10}{96}$

So, $\frac{5}{48} < \frac{7}{48} < \frac{5}{32}$, meaning April 13 has the least, April 11 has the greatest? Wait, no, wait: $\frac{5}{48}$ (April13) is less than $\frac{7}{48}$ (April12) and $\frac{15}{96}$ (April11 is $\frac{15}{96}$, April12 is $\frac{14}{96}$, April13 is $\frac{10}{96}$). Wait, I miscalculated April11: $\frac{5}{8} \div 4 = \frac{5}{32} = \frac{15}{96}$, April12: $\frac{7}{8} \div 6 = \frac{7}{48} = \frac{14}{96}$, April13: $\frac{5}{16} \div 3 = \frac{5}{48} = \frac{10}{96}$. So the order from least to greatest is April13 ($\frac{10}{96}$), April12 ($\frac{14}{96}$), April11 ($\frac{15}{96}$). So least is April13, greatest is April11.

Answer:

The day with the least amount of rainfall per hour is April 13.
The day with the greatest amount of rainfall per hour is April 11.