QUESTION IMAGE
Question
the table shows the gpa of several students and the number of hours they spend watching television each week. based on the table, what is the best prediction of a students gpa if the student watches 14 hours of television each week? 2.1 2.3 2.7 3.3
Step1: Analyze the trend
As the number of hours of TV watching (\(x\)) increases, the GPA (\(y\)) generally decreases. For example, when \(x = 3,y=3.5\); when \(x = 5,y = 3.4\); when \(x=10,y = 3.0\); when \(x = 12,y=2.7\).
Step2: Estimate for \(x = 14\)
Since the trend is a decrease in GPA with an increase in TV - watching hours. When \(x = 12,y = 2.7\). If we assume a linear - like trend (even though with only 4 data points it's a rough estimate), as \(x\) increases from 12 to 14 (an increase of 2), and looking at previous differences (e.g., from \(x = 10\) to \(x = 12\), \(y\) decreased by \(3.0−2.7 = 0.3\)). A further increase in \(x\) would lead to a further decrease in \(y\). A value less than \(2.7\) is more likely. Among the options, \(2.1\) and \(2.3\) are less than \(2.7\). But if we consider the rate of change (not a strict calculation, just a trend - based guess), if we assume a somewhat consistent rate of decrease (for example, if we consider the change from \(x=10\) (\(y = 3.0\)) to \(x = 12\) (\(y=2.7\)): \(\Delta x=2,\Delta y=- 0.3\)). If we extend this (very roughly) for \(x = 14\) (another \(\Delta x = 2\) from \(x = 12\)), a decrease of about \(0.3\) more would be too much (since it's a non - linear real - world relationship), but a small decrease. If we consider that when \(x\) is larger, the impact might be more (but still a rough guess). If we look at the fact that when \(x\) increases, \(y\) decreases, and \(2.1\) is a more significant decrease than \(2.3\). But if we consider the data:
Let's calculate the mean of \(y\) values: \(\bar{y}=\frac{3.0 + 3.4+3.5 + 2.7}{4}=\frac{12.6}{4}=3.15\). The values of \(y\) are \(3.0,3.4,3.5,2.7\). As \(x\) increases, \(y\) decreases. When \(x = 12,y = 2.7\). A student who watches more TV (\(x = 14\)) will have a lower GPA than \(2.7\). Among the options \(2.1\) and \(2.3\), if we assume a slow rate of decrease (since the change from \(x = 10\) to \(x = 12\) is a decrease of \(0.3\) in \(y\) for an increase of \(2\) in \(x\)), a decrease of \(0.4\) (from \(y = 2.7\) to \(y=2.3\)) for an increase of \(2\) in \(x\) (from \(x = 12\) to \(x = 14\)) is a more reasonable rough estimate compared to a decrease of \(0.6\) (to \(y = 2.1\)).
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