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QUESTION IMAGE

the table below shows the number of survey subjects who have received a…

Question

the table below shows the number of survey subjects who have received and not received a speeding ticket in the last year, and the color of their cars.

find the probability that a randomly chosen person:
a) has a red car.
b) has a speeding ticket.
c) has a speeding ticket given they have a red car.
d) has a red car given they have a speeding ticket.
e) has a red car and got a speeding ticket.
f) has a red car or got a speeding ticket.

write your answers in decimal form, rounded to the nearest thousandth.

Explanation:

Step1: Probability formula

The probability formula is \(P(A)=\frac{n(A)}{n(S)}\), where \(n(A)\) is the number of elements in event \(A\) and \(n(S)\) is the total number of elements in the sample space.

Step2: Part (a)

For the probability of having a red car, \(n(A) = 280\) (total number of red - car owners) and \(n(S)=563\). So \(P(\text{Red Car})=\frac{280}{563}\approx0.497\)

Step3: Part (b)

For the probability of having a speeding ticket, \(n(A) = 258\) (total number of speeding - ticket receivers) and \(n(S) = 563\). So \(P(\text{Speeding Ticket})=\frac{258}{563}\approx0.458\)

Step4: Part (c)

For conditional probability \(P(A|B)=\frac{P(A\cap B)}{P(B)}\). Here \(A\) is "having a speeding ticket" and \(B\) is "having a red car". \(P(A\cap B)=\frac{171}{563}\), \(P(B)=\frac{280}{563}\). Then \(P(\text{Speeding Ticket}|\text{Red Car})=\frac{171}{280}\approx0.611\)

Step5: Part (d)

For \(P(\text{Red Car}|\text{Speeding Ticket})\), \(P(A\cap B)=\frac{171}{563}\), \(P(B)=\frac{258}{563}\). Then \(P(\text{Red Car}|\text{Speeding Ticket})=\frac{171}{258}\approx0.663\)

Step6: Part (e)

For \(P(\text{Red Car and Speeding Ticket})\), \(n(A\cap B) = 171\) and \(n(S)=563\). So \(P(\text{Red Car and Speeding Ticket})=\frac{171}{563}\approx0.304\)

Step7: Part (f)

For \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\). \(P(A)=\frac{280}{563}\), \(P(B)=\frac{258}{563}\), \(P(A\cap B)=\frac{171}{563}\). Then \(P(\text{Red Car or Speeding Ticket})=\frac{280 + 258-171}{563}=\frac{367}{563}\approx0.652\)

Answer:

a) \(0.497\)
b) \(0.458\)
c) \(0.611\)
d) \(0.663\)
e) \(0.304\)
f) \(0.652\)