Question

suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. the object moves with constant acceleration. which part of a velocity vs. time graph can be used to calculate the displacement of the object? the area of the rectangle under the line the area of the rectangle above the line the area of the rectangle plus the area of the triangle under the line the area of the rectangle plus the area of the triangle above the line

Explanation:

On a velocity - time graph, for an object with non - zero initial velocity and constant acceleration, the displacement is given by the area under the graph. The initial velocity forms the height of a rectangle and the change in velocity over time forms a triangle below the line. The sum of the area of the rectangle (due to initial velocity) and the area of the triangle (due to the increase in velocity) gives the displacement.

Answer:

the area of the rectangle plus the area of the triangle under the line