suppose a $0.019\text{ m}$ aqueous solution of sulfuric acid ($\text{h}_2\text{so}_4$) is prepared. calculate the equilibrium molarity of $\text{so}_4^{2-}$. youll find information on the properties of sulfuric acid in the aleks data resource.

round your answer to 2 significant digits.

Question

suppose a $0.019\text{ m}$ aqueous solution of sulfuric acid ($\text{h}_2\text{so}_4$) is prepared. calculate the equilibrium molarity of $\text{so}_4^{2-}$. youll find information on the properties of sulfuric acid in the aleks data resource.

round your answer to 2 significant digits.

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Acid Dissociation", "Weak Acid Equilibrium", "Polyprotic Acid Equilibrium" ], "new_concepts": [], "current_concepts": [ "Acid Dissociation", "Weak Acid Equilibrium", "Polyprotic Acid Equilibrium" ] } ## Definir las reacciones de disociación del ácido sulfúrico $$ \begin{aligned} &\text{Primera disociación (completa):}\ &\mathrm{H_2SO_4(aq) ightarrow H^+(aq) + HSO_4^-(aq)}\ &[\mathrm{H^+}]_0 = 0.019\text{ M},\quad [\mathrm{HSO_4^-}]_0 = 0.019\text{ M}\ \ &\text{Segunda disociación (equilibrio débil):}\ &\mathrm{HSO_4^-(aq) ightleftharpoons H^+(aq) + SO_4^{2-}(aq)}\ &K_{a2} = 1.2 \times 10^{-2} \end{aligned} $$ ## Establecer la tabla de equilibrio para la segunda disociación $$ \begin{aligned} &\begin{array}{lccc} \text{Especie} & \mathrm{HSO_4^-} & \mathrm{H^+} & \mathrm{SO_4^{2-}} \ \hline \text{Inicial (M)} & 0.019 & 0.019 & 0 \ \text{Cambio (M)} & -x & +x & +x \ \text{Equilibrio (M)} & 0.019 - x & 0.019 + x & x \end{array}\ \ &K_{a2} = \frac{[\mathrm{H^+}][\mathrm{SO_4^{2-}}]}{[\mathrm{HSO_4^-}]} = \frac{(0.019 + x)x}{0.019 - x} = 0.012 \end{aligned} $$ ## Resolver para x $$ \begin{aligned} &(0.019 + x)x = 0.012(0.019 - x)\ &x^2 + 0.019x = 0.000228 - 0.012x\ &x^2 + 0.031x - 0.000228 = 0\ &x = \frac{-0.031 + \sqrt{0.031^2 - 4(1)(-0.000228)}}{2}\ &x = \frac{-0.031 + \sqrt{0.000961 + 0.000912}}{2}\ &x = \frac{-0.031 + \sqrt{0.001873}}{2} \approx \frac{-0.031 + 0.043278}{2} \approx 0.006139\text{ M}\ &[\mathrm{SO_4^{2-}}] \approx 6.1 \times 10^{-3}\text{ M} \end{aligned} $$ Suppose a $0.019\text{ M}$ aqueous solution of sulfuric acid ($\mathrm{H_2SO_4}$) is prepared. Calculate the equilibrium molarity of $\mathrm{SO_4^{2-}}$. Round your answer to 2 significant digits. $6.1 \times 10^{-3}$ $\text{M}$ { "subject": "Natural Science", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Natural Science", "Chemistry", "Polyprotic Acid Equilibrium" ] }

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Question

Explanation:

Definir las reacciones de disociación del ácido sulfúrico

Establecer la tabla de equilibrio para la segunda disociación

Resolver para x

Answer: