Question

subtract.
ex. \\(\frac{3}{4} - \frac{1}{8} = \frac{6}{8} - \frac{1}{8} = \frac{5}{8}\\)
(1) \\(\frac{3}{4} - \frac{5}{8} = \frac{\square}{8} - \frac{5}{8} =\\)
(2) \\(\frac{3}{4} - \frac{3}{8} =\\)
(3) \\(\frac{1}{4} - \frac{1}{8} =\\)
(4) \\(\frac{1}{3} - \frac{1}{9} =\\)
(5) \\(\frac{1}{3} - \frac{2}{9} =\\)
(6) \\(\frac{2}{3} - \frac{4}{9} =\\)

Explanation:

(1) Step1: Find common denominator

To subtract \(\frac{3}{4}-\frac{5}{8}\), we need a common denominator. The least common denominator of 4 and 8 is 8. Convert \(\frac{3}{4}\) to eighths: \(\frac{3}{4}=\frac{3\times2}{4\times2}=\frac{6}{8}\). So the first blank is 6.

(1) Step2: Subtract the fractions

Now we have \(\frac{6}{8}-\frac{5}{8}=\frac{6 - 5}{8}=\frac{1}{8}\).

(2) Step1: Find common denominator

For \(\frac{3}{4}-\frac{3}{8}\), the common denominator is 8. Convert \(\frac{3}{4}\) to \(\frac{6}{8}\) (as \(3\times2 = 6\), \(4\times2 = 8\)).

(2) Step2: Subtract the fractions

\(\frac{6}{8}-\frac{3}{8}=\frac{6 - 3}{8}=\frac{3}{8}\).

(3) Step1: Find common denominator

For \(\frac{1}{4}-\frac{1}{8}\), the common denominator is 8. Convert \(\frac{1}{4}\) to \(\frac{2}{8}\) (since \(1\times2 = 2\), \(4\times2 = 8\)).

(3) Step2: Subtract the fractions

\(\frac{2}{8}-\frac{1}{8}=\frac{2 - 1}{8}=\frac{1}{8}\).

(4) Step1: Find common denominator

For \(\frac{1}{3}-\frac{1}{9}\), the common denominator is 9. Convert \(\frac{1}{3}\) to \(\frac{3}{9}\) (as \(1\times3 = 3\), \(3\times3 = 9\)).

(4) Step2: Subtract the fractions

\(\frac{3}{9}-\frac{1}{9}=\frac{3 - 1}{9}=\frac{2}{9}\).

(5) Step1: Find common denominator

For \(\frac{1}{3}-\frac{2}{9}\), the common denominator is 9. Convert \(\frac{1}{3}\) to \(\frac{3}{9}\) (since \(1\times3 = 3\), \(3\times3 = 9\)).

(5) Step2: Subtract the fractions

\(\frac{3}{9}-\frac{2}{9}=\frac{3 - 2}{9}=\frac{1}{9}\).

(6) Step1: Find common denominator

For \(\frac{2}{3}-\frac{4}{9}\), the common denominator is 9. Convert \(\frac{2}{3}\) to \(\frac{6}{9}\) (as \(2\times3 = 6\), \(3\times3 = 9\)).

(6) Step2: Subtract the fractions

\(\frac{6}{9}-\frac{4}{9}=\frac{6 - 4}{9}=\frac{2}{9}\).

Answer:

(1) \(\frac{3}{4}-\frac{5}{8}=\frac{\boldsymbol{6}}{8}-\frac{5}{8}=\boldsymbol{\frac{1}{8}}\)
(2) \(\frac{3}{4}-\frac{3}{8}=\boldsymbol{\frac{3}{8}}\)
(3) \(\frac{1}{4}-\frac{1}{8}=\boldsymbol{\frac{1}{8}}\)
(4) \(\frac{1}{3}-\frac{1}{9}=\boldsymbol{\frac{2}{9}}\)
(5) \(\frac{1}{3}-\frac{2}{9}=\boldsymbol{\frac{1}{9}}\)
(6) \(\frac{2}{3}-\frac{4}{9}=\boldsymbol{\frac{2}{9}}\)