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subtract. (9t² + 8t + 9) - (t² + 6t + 6)

Question

subtract.
(9t² + 8t + 9) - (t² + 6t + 6)

Explanation:

Step1: Distribute the negative sign

To subtract the second polynomial from the first, we distribute the negative sign to each term in the second polynomial:
\((9t^{2}+8t + 9)-t^{2}-6t - 6\)

Step2: Combine like terms

  • For the \(t^{2}\) terms: \(9t^{2}-t^{2}=8t^{2}\)
  • For the \(t\) terms: \(8t-6t = 2t\)
  • For the constant terms: \(9 - 6=3\)

Step3: Write the result

Combine the combined like terms: \(8t^{2}+2t + 3\)

Answer:

\(8t^{2}+2t + 3\)