Question

student force (n) distance (m) time (s)
w 10 4 5
x 5 8 8
y 5 12 10
z 1 14 8
which two students did the same amount of work?
a students w and x
b students x and y
c students y and z

Explanation:

Step1: Recall work - formula

Work \(W = F\times d\) (where \(F\) is force and \(d\) is distance).

Step2: Calculate work for student W

For student W, \(F = 10\ N\) and \(d=4\ m\), so \(W_W=F\times d = 10\times4=40\ J\).

Step3: Calculate work for student X

For student X, \(F = 5\ N\) and \(d = 8\ m\), so \(W_X=F\times d=5\times8 = 40\ J\).

Step4: Calculate work for student Y

For student Y, \(F = 5\ N\) and \(d = 12\ m\), so \(W_Y=F\times d=5\times12=60\ J\).

Step5: Calculate work for student Z

For student Z, \(F = 1\ N\) and \(d = 14\ m\), so \(W_Z=F\times d=1\times14 = 14\ J\).

Answer:

A. students W and X