Question

a student earned grades of b, a, c, and d. those courses had these corresponding numbers of credit hours: 5, 4, 3, and 1. the grading system assigns quality points to letter grades as follows: a = 4, b = 3, c = 2, d = 1, f = 0. compute the grade - point average (gpa). if the deans list requires a gpa of 3.20 or greater, did this student make the deans list? the students gpa is (type an integer or decimal rounded to two decimal places as needed)

Explanation:

Step1: Calculate the total quality points

Multiply each grade - point value by its corresponding credit - hour and sum them up.
For grade \(A\) (\(4\) quality points) with \(5\) credit - hours: \(4\times5 = 20\)
For grade \(B\) (\(3\) quality points) with \(4\) credit - hours: \(3\times4=12\)
For grade \(C\) (\(2\) quality points) with \(3\) credit - hours: \(2\times3 = 6\)
For grade \(D\) (\(1\) quality point) with \(1\) credit - hour: \(1\times1=1\)
The total quality points \(Q=\sum_{i = 1}^{n}q_ih_i=20 + 12+6 + 1=39\)

Step2: Calculate the total credit - hours

Sum up the credit - hours of all courses.
The total credit - hours \(H=\sum_{i = 1}^{n}h_i=5 + 4+3 + 1=13\)

Step3: Calculate the GPA

The formula for GPA is \(GPA=\frac{Q}{H}\)
Substitute \(Q = 39\) and \(H = 13\) into the formula: \(GPA=\frac{39}{13}=3.00\)

Answer:

The student's GPA is \(3.00\). Since \(3.00<3.20\), the student did not make the dean's list.