Question

a student considers how many people enter a particular bank during the lunch hour and how many exit. she decides to run a simulation. she assigns the value 0 to represent a person entering the bank and 1 to represent a person exiting the bank. based on a simulation for the first 20 people she observes, estimate the probability she will see a person entering the bank. 0 1 0 0 0 1 1 1 0 1 0 0 0 1 0 1 0 0 1 0 (1 point) 0.400 0.250 0.500 0.600

Explanation:

Step1: Count the number of 0s

Count the number of 0s (representing people entering) in the sequence \(0\ 1\ 0\ 0\ 0\ 1\ 1\ 1\ 0\ 1\ 0\ 0\ 0\ 1\ 0\ 1\ 0\ 0\ 1\ 0\). There are 12 zeros.

Step2: Calculate the probability

The probability \(P\) of an event is given by \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\). Here, the number of favorable outcomes (people entering, i.e., 0s) is \(n = 12\), and the total number of outcomes (total number of people observed) is \(N=20\). So, \(P=\frac{12}{20}=0.6\)

Answer:

0.600