QUESTION IMAGE
Question
step statement reason
1 ( bd = bc + cd ) multiplication and division properties
2 ( eg = ef + fg ) substitution property
3 ( bd = eg ) given
4 ( bc + cd = ef + fg ) segment addition property
5 ( bc = fg ) given
6 ( fg + cd = ef + fg ) addition and subtraction properties
7 ( cd = ef ) reflexive property
Step1: Segment Addition Property
Segments can be added. So, \(BD = BC + CD\) and \(EG=EF + FG\) are based on the Segment Addition Property.
Step2: Substitution
Since \(BD = EG\) (given), substitute \(BD\) with \(BC + CD\) and \(EG\) with \(EF + FG\) in the equation \(BD = EG\). We get \(BC + CD=EF + FG\).
Step3: Substitute \(BC\) with \(FG\)
Given \(BC = FG\), substitute \(BC\) in \(BC + CD=EF + FG\). So, \(FG + CD=EF + FG\).
Step4: Subtraction Property of Equality
Subtract \(FG\) from both sides of the equation \(FG + CD=EF + FG\). Using the subtraction property of equality (\(a + b=c + b\Rightarrow a=c\)), we get \(CD = EF\).
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The correct reasons for each step should be:
- Segment Addition Property
- Segment Addition Property
- Given
- Substitution Property
- Given
- Substitution Property
- Subtraction Property of Equality