Question

statements 1 and 2 are true conditional statements. statement 1: if a figure is a square, then it is a rectangle. statement 2: if a figure is a rectangle, then it is a parallelogram. which conclusion is valid? if figure a is a square, then figure a is a parallelogram. if figure a is not a square, then figure a is not a parallelogram. if figure a is a parallelogram, then figure a is a square. if figure a is a rectangle, then figure a is a square.

Explanation:

Step1: Analyze the first conditional statement

Statement 1: Square → Rectangle (If a figure is a square, then it is a rectangle).

Step2: Analyze the second conditional statement

Statement 2: Rectangle → Parallelogram (If a figure is a rectangle, then it is a parallelogram).

Step3: Use the law of syllogism

By the law of syllogism, if \(p
ightarrow q\) and \(q
ightarrow r\), then \(p
ightarrow r\). Here \(p\) is "a figure is a square", \(q\) is "a figure is a rectangle" and \(r\) is "a figure is a parallelogram". So Square → Parallelogram.

Answer:

If Figure A is a square, then Figure A is a parallelogram.