Question

for a standard normal distribution (using the normal distribution table), find $p(-1.94 < z < 2.86)$, the percent of data values between $z = -1.94$ and $z = 2.86$.
the normal distribution table gives the decimal area between $z = -1.94$ and $z = 2.86$ as $p(-1.94 < z < 2.86) = \square$.
converted to percent (\\%), the percent of data values between $z = -1.94$ and $z = 2.86$ is $p(-1.94 < z < 2.86) = \square\\%$.
enter an integer or decimal number more...
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Explanation:

Step1: Find area for z=2.86

Area to left of z=2.86 is 0.9979.

Step2: Find area for z=-1.94

Area to left of z=-1.94 is 0.0262.

Step3: Calculate between area

Subtract: 0.9979 - 0.0262 = 0.9717.

Step4: Convert to percentage

Multiply by 100: 0.9717 × 100 = 97.17.

Answer:

0.9717
97.17