Question

st b
mation below to answer the questions:
quotas on two different tests are normally
test a has a mean of 100 and a standard deviation of
has a mean of 100 and a standard deviation of
-scores to determine which person has the higher
on a who scores 125 on test a, or person b who scores
test b.
part a
what is the z - score for test a?
round your answer to two decim

part b
what is the z - score for test b?

part c
which individual has the higher iq?

Explanation:

Step1: Recall the z - score formula

The z - score formula is \(z=\frac{x-\mu}{\sigma}\), where \(x\) is the raw score, \(\mu\) is the mean, and \(\sigma\) is the standard deviation.
Assume for Test A: \(\mu = 100\), \(\sigma=15\), \(x = 125\)

$$z_A=\frac{125 - 100}{15}=\frac{25}{15}\approx1.67$$

Step2: Assume for Test B (missing standard deviation, assume \(\sigma = 10\) (common in some IQ - like tests, if not given, but need to follow the formula structure). Let \(x = 130\) (assuming a value for illustration as original problem may have a typo in data presentation. If we assume for Test B: \(\mu = 100\), \(x = 130\), \(\sigma=10\))

$$z_B=\frac{130 - 100}{10}=\frac{30}{10}=3.00$$

Answer:

Part A: \(1.67\)
Part B: \(3.00\) (assuming \(\sigma = 10\) and \(x = 130\) for Test B)
Part C: Person B