Question

sss
sas
aa
none of the above; the triangles cannot be proven similar

Explanation:

Step1: Find the third angle of the first triangle

In a triangle, the sum of angles is \(180^{\circ}\). For the triangle with angles \(43^{\circ}\) and \(102^{\circ}\), let the third angle be \(x\). Then \(x = 180-(43 + 102)=35^{\circ}\).

Step2: Find the third angle of the second triangle

Since vertical angles are equal (at point \(W\)), and one angle is \(43^{\circ}\). Let the third angle of the second triangle be \(y\). Using the angle - sum property of a triangle (\(180^{\circ}\)), if we assume the two triangles are \(\triangle T\) - something and \(\triangle V\) - something. The two triangles have two pairs of equal angles (\(43^{\circ}\) and the vertical angles (which are equal)).

Answer:

AA