Question

square roots
\sqrt{60} = ?
betweens
1&2 2&3 3&4 4&5 5&6 6&7 7&8 8&9 9&10
0 1 2 3 4 5 6 7 8 9 10 11

Explanation:

Step1: Recall square values

Find perfect squares around 60. $7^2 = 49$, $8^2 = 64$.

Step2: Compare with 60

Since $49 < 60 < 64$, $\sqrt{49} < \sqrt{60} < \sqrt{64}$, so $7 < \sqrt{60} < 8$.

Step3: Identify the range

The range $7\&8$ matches $7 < \sqrt{60} < 8$.

Answer:

$7\&8$