Question

square roots
√9 = ?
betweens
1&2 2&3 3&4 4&5 5&6 6&7 7&8 8&9 9&10
0 1 2 3 4 5 6 7 8 9 10 11

Explanation:

Step1: Recall square root definition

The square root of a number \( x \), denoted \( \sqrt{x} \), is a value \( y \) such that \( y^2 = x \).

Step2: Find \( y \) for \( x = 9 \)

We need to find \( y \) where \( y^2 = 9 \). Testing integers: \( 3^2 = 9 \) (since \( 3\times3 = 9 \)) and also \( (-3)^2 = 9 \), but in the context of the number line (with non - negative numbers 0 - 11 shown), we consider the principal (non - negative) square root. So \( \sqrt{9}=3 \).

Answer:

3