Question

a species of grass has a haploid number of 18. how many different types of gametes can be produced from meiosis in a diploid individual just with independent assortment (no crossing over)?

Explanation:

Step1: Recall the formula for the number of gametes

The formula for the number of different types of gametes produced due to independent assortment (without crossing - over) is \(2^{n}\), where \(n\) is the haploid number of chromosomes.

Step2: Substitute the value of \(n\)

Given that the haploid number \(n = 18\). Then the number of gametes \(=2^{18}\)

Answer:

\(2^{18}\)