Question

solving a triangle given sas information
using the law of cosines, ( a approx ) _, rounded
to the nearest tenth.
done

Explanation:

Step1: Recall the law of cosines formula

The law of cosines formula is \(a^{2}=b^{2}+c^{2}-2bc\cos A\). In this triangle, \(b = 3.7\), \(c = 4.0\), and \(A=33^{\circ}\).

Step2: Substitute the values into the formula

$$
LATEXBLOCK0
$$

Step3: Solve for \(a\)

Take the square - root of both sides: \(a=\sqrt{4.86448}\approx2.2\)

Answer:

\(2.2\)