Question

solve for p. 6|p| > 6. write a compound inequality like 1 < x < 3 or like x < 1 or x > 3. use integers, proper fractions, or improper fractions in simplest form.

Explanation:

Step1: Isolate the absolute - value.

Divide both sides of $6|p|>6$ by 6: $\frac{6|p|}{6}>\frac{6}{6}$, which simplifies to $|p| > 1$.

Step2: Solve the absolute - value inequality.

If $|p|>1$, then $p>1$ or $p < - 1$ according to the rule that if $|x|>a$ ($a>0$), then $x > a$ or $x < - a$.

Answer:

$p < - 1$ or $p>1$