Question

solve for x.
view solution history
\\(\frac{1}{8}x = \frac{7}{8}x + 6\\)
divide both sides :divide both sides by what?
\\(\frac{-\frac{3}{4}x}{square} = \frac{6}{square}\\)

Explanation:

Step1: Solve the original equation for x terms

Start with \(\frac{1}{8}x = \frac{7}{8}x + 6\). Subtract \(\frac{7}{8}x\) from both sides: \(\frac{1}{8}x - \frac{7}{8}x=\frac{7}{8}x + 6-\frac{7}{8}x\). Simplify: \(\frac{1 - 7}{8}x=6\) → \(-\frac{6}{8}x = 6\) → \(-\frac{3}{4}x=6\).

Step2: Determine what to divide by

To solve for \(x\), we divide both sides by \(-\frac{3}{4}\) (or multiply by \(-\frac{4}{3}\)). So for the equation \(\frac{-\frac{3}{4}x}{\square}=\frac{6}{\square}\), we divide both sides by \(-\frac{3}{4}\), so both denominators are \(-\frac{3}{4}\).

Answer:

For the first box (denominator of \(-\frac{3}{4}x\)): \(-\frac{3}{4}\)
For the second box (denominator of \(6\)): \(-\frac{3}{4}\)