Question

solve $x^2 - 14 = -14$ using square roots. select the solution(s).
$\square\\ x = -10$ $\square\\ x = -5$ $\square\\ x = -1$ $\square\\ x = 3$
$\square\\ x = -8$ $\square\\ x = -4$ $\square\\ x = 0$ $\square\\ x = 4$
$\square\\ x = -7$ $\square\\ x = -3$ $\square\\ x = 1$ $\square\\ x = 5$
$\square\\ x = -6$ $\square\\ x = -2$ $\square\\ x = 2$ $\square\\ x = 6$

Explanation:

Step1: Isolate \(x^2\)

Add 14 to both sides of the equation \(x^2 - 14 = -14\).
\(x^2 - 14 + 14 = -14 + 14\)
Simplifying, we get \(x^2 = 0\).

Step2: Solve for \(x\)

Take the square root of both sides. The square root of 0 is 0, so \(x = \sqrt{0} = 0\).

Answer:

\(x = 0\) (the option with \(x = 0\))