solve using elimination.
7x + y = -6
-7x + 7y = 14
(\square, \square)

Question

Accepted Answer

# Explanation:
## Step1: Add the two equations to eliminate $x$
The first equation is $7x + y = -6$ and the second is $-7x + 7y = 14$. When we add them together:
$$
\begin{align*}
(7x + y)+(-7x + 7y)&=-6 + 14\
7x + y-7x + 7y&=8\
8y&=8
\end{align*}
$$
## Step2: Solve for $y$
Divide both sides of $8y = 8$ by 8:
$$
y=\frac{8}{8}=1
$$
## Step3: Substitute $y = 1$ into the first equation to find $x$
Substitute $y = 1$ into $7x + y=-6$:
$$
\begin{align*}
7x+1&=-6\
7x&=-6 - 1\
7x&=-7\
x&=\frac{-7}{7}=-1
\end{align*}
$$
# Answer:
$(-1, 1)$

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QUESTION IMAGE

Question

Explanation:

Step1: Add the two equations to eliminate \(x\)

Step2: Solve for \(y\)

Step3: Substitute \(y = 1\) into the first equation to find \(x\)

Answer: