QUESTION IMAGE
Question
solve for y.
\frac{y - 7}{y + 2} + 1 = \frac{y - 5}{y + 3}
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o solution\.
y = \square
Step1: Eliminate denominators
Multiply all terms by $(y+2)(y+3)$:
$$(y-7)(y+3) + (y+2)(y+3) = (y-5)(y+2)$$
Step2: Expand all polynomials
$$(y^2 -4y -21) + (y^2 +5y +6) = y^2 -3y -10$$
Step3: Simplify left-hand side
$$2y^2 + y -15 = y^2 -3y -10$$
Step4: Rearrange to standard quadratic form
$$y^2 +4y -5 = 0$$
Step5: Factor the quadratic
$$(y+5)(y-1) = 0$$
Step6: Solve for y, check domain
Exclude $y=-2,-3$ (denominator zeros); solutions are valid.
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$y = -5, 1$