QUESTION IMAGE
Question
solve the system of equations below.
\\\
$$\begin{aligned}
3x + 4y &= 10 \\\\
6x - 2y &= 40
\\end{aligned}$$
\\
(6, -2)
(-2, -6)
(2, 6)
(2, -6)
Set up the system of equations
$$
LATEXBLOCK0
$$
Eliminate the variable y
Multiply Equation 2 by 2 and add it to Equation 1:
$$
LATEXBLOCK1
$$
Solve for y
Substitute \(x = 6\) into Equation 1:
$$
LATEXBLOCK2
$$
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- (A) (6,-2) (Correct answer)
- (B) (-2,-6)
- (C) (2,6)
- (D) (2,-6)