solve: $\sqrt3{8x - 2} = 4$

to solve this equation, first cube both sides.

$x = $
8.25
0.75
1.75
2.25
no real solutions

Question

solve: $\sqrt3{8x - 2} = 4$

to solve this equation, first cube both sides.

$x = $
8.25
0.75
1.75
2.25
no real solutions

Accepted Answer

{ "quality": "clear", "question_count": 2, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Solving Radical Equations", "Cube Root Equations" ], "new_concepts": [], "current_concepts": [ "Solving Radical Equations", "Cube Root Equations" ] } ## Cube both sides of the equation Using the *Cube Root Equations* knowledge point $$ \begin{aligned} \sqrt[3]{8x - 2} &= 4 \ (\sqrt[3]{8x - 2})^3 &= 4^3 \ 8x - 2 &= 64 \end{aligned} $$ ## Solve the linear equation for x Using the *Solving Radical Equations* knowledge point $$ \begin{aligned} 8x &= 64 + 2 \ 8x &= 66 \ x &= \frac{66}{8} \ x &= 8.25 \end{aligned} $$ ## Question 1 To solve this equation, first cube both sides. ## Question 2 (A) 8.25

(B) 0.75

(C) 1.75

(D) 2.25

(E) no real solutions

{ "subject": "Mathematics", "question_type": "Multi-part", "knowledge_point": [ "Mathematics", "Algebra", "Solving Radical Equations" ] }

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QUESTION IMAGE

Question

Explanation:

Cube both sides of the equation

Solve the linear equation for x

Answer:

Question 1

Question 2