Question

8.6 solve radical equations (homework)
score: 4/16 answered: 4/16
question 5
find all real solutions:
\\(\sqrt{4c - 6}-9 = 0\\)
\\(c=) (if no solution exists, enter dne)

Explanation:

Step1: Isolate the square - root term

Add 9 to both sides of the equation $\sqrt{4c - 6}-9 = 0$.
$\sqrt{4c - 6}=9$

Step2: Square both sides

Squaring both sides to eliminate the square - root.
$(\sqrt{4c - 6})^2=9^2$
$4c - 6 = 81$

Step3: Solve for c

Add 6 to both sides: $4c=81 + 6=87$.
Then divide both sides by 4: $c=\frac{87}{4}=21.75$

Answer:

$21.75$