Question

solve the problem.
the sum of three consecutive integers is 393. find the integers. give the equation used to solve for the integers.
○ x+x+x=393
○ 2x+(2x+1)+(2x+2)=393
○ x+(x+1)+(x+2)=393
○ x+(x+2)+(x+4)=393
○ x+3=393

Explanation:

Step1: Define consecutive integers

Let the first integer be \( x \). Consecutive integers increase by 1, so the next two are \( x + 1 \) and \( x + 2 \).

Step2: Set up the equation

The sum of the three integers is \( x+(x + 1)+(x + 2) \), and this equals 393. So the equation is \( x+(x + 1)+(x + 2)=393 \).

Step3: Solve the equation (optional for identifying the correct option)

Combine like terms: \( 3x+3 = 393 \). Subtract 3: \( 3x = 390 \). Divide by 3: \( x = 130 \). The integers are 130, 131, 132, confirming the equation is correct.

Answer:

C. \( x+(x+1)+(x+2)=393 \) (assuming the options are labeled A to E with this as option C; if labels differ, use the correct label with the equation \( x+(x+1)+(x+2)=393 \))