Question

solve the inequality and graph the solution.
\\(\frac{v + 2}{2}\leq - 3\\)
plot the endpoints. select an endpoint to change it from closed to open. select the middle of the segment, ray, or line to delete it.

Explanation:

Step1: Multiply both sides by 2

$2\times\frac{v + 2}{2}\leq2\times(-3)$
$v + 2\leq - 6$

Step2: Subtract 2 from both sides

$v+2 - 2\leq-6 - 2$
$v\leq - 8$

Answer:

The solution of the inequality is $v\leq - 8$. On the number - line, we plot a closed circle at $-8$ (because the inequality is $\leq$) and draw a ray to the left of $-8$.