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solve the following system of linear equations by substitution and dete…

Question

solve the following system of linear equations by substitution and determine whether the system has one solution, no solution, or an infinite number of solutions. if the system has one solution, find the solution.
\

$$\begin{cases} y = 4x - 23 \\\\ y = -9x + 29 \\end{cases}$$

answer
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\bigcirc one solution \quad (\boxed{\quad}, \boxed{\quad})
\bigcirc no solution
\bigcirc infinite number of solutions

Explanation:

Step1: Substitute y from first equation into second

Since \( y = 4x - 23 \) and \( y = -9x + 29 \), set them equal: \( 4x - 23 = -9x + 29 \)

Step2: Solve for x

Add \( 9x \) to both sides: \( 4x + 9x - 23 = 29 \) → \( 13x - 23 = 29 \)
Add 23 to both sides: \( 13x = 29 + 23 \) → \( 13x = 52 \)
Divide by 13: \( x = \frac{52}{13} = 4 \)

Step3: Find y using x = 4

Substitute \( x = 4 \) into \( y = 4x - 23 \): \( y = 4(4) - 23 = 16 - 23 = -7 \)

Answer:

One Solution \((4, -7)\)