solve the following quadratic function by utilizing the square root method.

\y = 4(x - 2)^2 - 28\

\x = ? \pm \sqrt{\quad}\

Question

solve the following quadratic function by utilizing the square root method.

\y = 4(x - 2)^2 - 28\

\x = ? \pm \sqrt{\quad}\

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Square Root Method", "Solving Quadratic Functions" ], "new_concepts": [], "current_concepts": [ "Square Root Method", "Solving Quadratic Functions" ] } ## Set the quadratic function to zero $$ 4(x - 2)^2 - 28 = 0 $$ ## Isolate the squared term $$ \begin{aligned} 4(x - 2)^2 &= 28 \ (x - 2)^2 &= 7 \end{aligned} $$ ## Apply the square root method $$ \begin{aligned} x - 2 &= \pm\sqrt{7} \ x &= 2 \pm\sqrt{7} \end{aligned} $$ Solve the following quadratic function by utilizing the square root method. $y = 4(x - 2)^2 - 28$ $x =$ $2$ $\pm \sqrt{\text{\phantom{a}}}$$7$ { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Solving Quadratic Functions" ] }

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QUESTION IMAGE

Question

Explanation:

Set the quadratic function to zero

Isolate the squared term

Apply the square root method

Answer: