QUESTION IMAGE
Question
solve the equation and check the solution. 7 = z + 5; z = \square
Step1: Isolate z by subtracting 5
To solve for \( z \) in the equation \( 7 = z + 5 \), we subtract 5 from both sides. This is based on the subtraction property of equality, which states that if \( a = b \), then \( a - c = b - c \). So, we have:
\( 7 - 5 = z + 5 - 5 \)
Simplifying both sides:
\( 2 = z \)
Step2: Check the solution
Now, we check if \( z = 2 \) satisfies the original equation. Substitute \( z = 2 \) into the right - hand side of the equation \( 7 = z + 5 \):
\( z + 5=2 + 5 = 7 \)
The left - hand side of the original equation is 7, and the right - hand side after substitution is also 7. So, the solution is correct.
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\( z = 2 \)