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solve for x in the equation $-\frac{3}{6}x + \frac{1}{6} = -\frac{2}{6}…

Question

solve for x in the equation $-\frac{3}{6}x + \frac{1}{6} = -\frac{2}{6}$. $x = \square$

Explanation:

Step1: Subtract 1/6 from both sides

$-\frac{3}{6}x + \frac{1}{6} - \frac{1}{6} = -\frac{2}{6} - \frac{1}{6}$
$-\frac{3}{6}x = -\frac{3}{6}$

Step2: Simplify fractions

$-\frac{1}{2}x = -\frac{1}{2}$

Step3: Multiply both sides by -2

$x = 1$

Answer:

1