Question

solve the dosage by weight conversion problem.
the physician has ordered a syrup orally at 0.3 milligrams per kilogram three times a day. the client weighs 30 pounds 4 ounces.
a) what is the weight in kilograms?
b) what is the daily dose?
c) what is the individual dose?
a) the clients weight in kilograms is 13.72.
(round to the nearest hundredth as needed.)
b) the daily dose is □ milligrams.
(type an integer or decimal rounded to the nearest tenth as needed.)

Explanation:

Step1: Calculate the daily dose

We know the weight in kilograms is \(13.72\) kg and the dose is \(0.3\) mg/kg/day.
The formula for the daily dose \(D\) is \(D=\text{weight (kg)}\times\text{dose per kg}\times\text{frequency}\). Here, the frequency is \(3\) times a day. But since the dose per kg is given as a daily - based (implied by the problem structure, as we first convert weight and then calculate dose), if we consider the formula \(D = \text{weight (kg)}\times\text{dose per kg}\), where the dose per kg is \(0.3\) mg/kg (and the three - times - a - day is for part c).
\(D=13.72\times0.3\)

Step2: Perform the multiplication

\(13.72\times0.3=(13 + 0.72)\times0.3=13\times0.3+0.72\times0.3\)
\(13\times0.3 = 3.9\) and \(0.72\times0.3=0.216\)
\(D=3.9 + 0.216=4.116\approx4.1\) (rounded to the nearest tenth)

Answer:

\(4.1\)