Question

solve for x. 8 - \sqrt3{9x} = 11 x = \square submit

Explanation:

Step1: Isolate the cube root term

Subtract 8 from both sides of the equation \(8 - \sqrt[3]{9x}=11\).
\(8 - \sqrt[3]{9x}-8 = 11 - 8\)
Simplify to get \(-\sqrt[3]{9x}=3\).

Step2: Eliminate the negative sign

Multiply both sides by -1:
\(\sqrt[3]{9x}=- 3\).

Step3: Cube both sides

Cube both sides of the equation to eliminate the cube root. \((\sqrt[3]{9x})^3=(-3)^3\)
Which simplifies to \(9x=-27\).

Step4: Solve for x

Divide both sides by 9:
\(x=\frac{-27}{9}\)
Simplify the fraction to get \(x = - 3\).

Answer:

\(-3\)