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solve 88 = 2y², where y is a real number. round your answer to the near…

Question

solve 88 = 2y², where y is a real number. round your answer to the nearest hundredth. if there is more than one solution, separate them with commas. if there is no solution, click on
o solution\.

Explanation:

Step1: Isolate $y^{2}$

Divide both sides of the equation $88 = 2y^{2}$ by 2. We get $\frac{88}{2}=y^{2}$, so $y^{2}=44$.

Step2: Solve for $y$

Take the square - root of both sides. $y=\pm\sqrt{44}$. Simplify $\sqrt{44}=\sqrt{4\times11} = 2\sqrt{11}\approx2\times3.317 = 6.634$. Rounding to the nearest hundredth, $y\approx\pm6.63$.

Answer:

$y\approx6.63,-6.63$