7. solve $2(x + 3) = -4(x + 1)$ for $x$.

$x = -\frac{1}{3}$

$x = -\frac{5}{3}$

$x = \frac{5}{3}$

$x = \frac{1}{3}$

Question

7. solve $2(x + 3) = -4(x + 1)$ for $x$.

$x = -\frac{1}{3}$

$x = -\frac{5}{3}$

$x = \frac{5}{3}$

$x = \frac{1}{3}$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "multiple_choice_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Linear Equation Solving" ], "new_concepts": [], "current_concepts": [ "Linear Equation Solving" ] } ## Expand both sides of the equation $$ \begin{aligned} 2(x + 3) &= -4(x + 1) \ 2x + 6 &= -4x - 4 \end{aligned} $$ ## Isolate the variable terms $$ \begin{aligned} 2x + 4x &= -4 - 6 \ 6x &= -10 \end{aligned} $$ ## Solve for x $$ \begin{aligned} x &= -\frac{10}{6} \ x &= -\frac{5}{3} \end{aligned} $$

(A) $x = -\frac{1}{3}$

(B) $x = -\frac{5}{3}$

(C) $x = \frac{5}{3}$

(D) $x = \frac{1}{3}$

{ "subject": "Mathematics", "question_type": "Multiple Choice", "knowledge_point": [ "Mathematics", "Algebra", "Linear Equation Solving" ] }

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QUESTION IMAGE

Question

Explanation:

Expand both sides of the equation

Isolate the variable terms

Solve for x

Answer: