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solve for z. -11z ≥ 11

Question

solve for z. -11z ≥ 11

Explanation:

Step1: Divide both sides by -11

When dividing an inequality by a negative number, the inequality sign flips. So, divide both sides of \(-11z \geq 11\) by \(-11\): \(\frac{-11z}{-11} \leq \frac{11}{-11}\)

Step2: Simplify both sides

Simplify the left side: \(\frac{-11z}{-11} = z\). Simplify the right side: \(\frac{11}{-11} = -1\). So we get \(z \leq -1\)

Answer:

\(z \leq -1\)