Question

single replacement reaction worksheet
for each reaction use the activity series to complete
the reaction. if no reaction will occur, write
o
reaction\. make sure you balance your final
answer.

1. ag + kno₃ →
2. zn + agno₃ →
3. cl₂ + ki →
4. cu + feso₄ →
5. fe + pb(no₃)₂ →
6. cu + al₂(so₄)₃ →
7. al + pb(no₃)₂ →
8. cl₂ + nai →
9. fe + agc₂h₃o₂ →
10. al + cucl₂ →
11. br₂ + cai₂ →
12. fe + cuso₄ →
13. cl₂ + mgi₂ →

Explanation:

Step1: Check activity series

For single - replacement reactions, a metal (or non - metal) can replace another metal (or non - metal) in a compound if it is more reactive.

Step2: Analyze each reaction

Reaction 1: \(Ag + KNO_3\)

Silver (\(Ag\)) is less reactive than potassium (\(K\)) in the activity series. So, no reaction occurs.

Reaction 2: \(Zn+AgNO_3\)

Zinc (\(Zn\)) is more reactive than silver (\(Ag\)). The reaction is \(Zn + 2AgNO_3=Zn(NO_3)_2 + 2Ag\)

Reaction 3: \(Cl_2+KI\)

Chlorine (\(Cl_2\)) is more reactive than iodine (\(I_2\)). The reaction is \(Cl_2 + 2KI = 2KCl+I_2\)

Reaction 4: \(Cu + FeSO_4\)

Copper (\(Cu\)) is less reactive than iron (\(Fe\)). So, no reaction occurs.

Reaction 5: \(Fe+Pb(NO_3)_2\)

Iron (\(Fe\)) is more reactive than lead (\(Pb\)). The reaction is \(Fe + Pb(NO_3)_2=Fe(NO_3)_2 + Pb\)

Reaction 6: \(Cu+Al_2(SO_4)_3\)

Copper (\(Cu\)) is less reactive than aluminum (\(Al\)). So, no reaction occurs.

Reaction 7: \(Al + Pb(NO_3)_2\)

Aluminum (\(Al\)) is more reactive than lead (\(Pb\)). The reaction is \(2Al+3Pb(NO_3)_2 = 2Al(NO_3)_3+3Pb\)

Reaction 8: \(Cl_2+NaI\)

Chlorine (\(Cl_2\)) is more reactive than iodine (\(I_2\)). The reaction is \(Cl_2+2NaI = 2NaCl + I_2\)

Reaction 9: \(Fe+AgC_2H_3O_2\)

Iron (\(Fe\)) is more reactive than silver (\(Ag\)). The reaction is \(Fe + 2AgC_2H_3O_2=Fe(C_2H_3O_2)_2+2Ag\)

Reaction 10: \(Al+CuCl_2\)

Aluminum (\(Al\)) is more reactive than copper (\(Cu\)). The reaction is \(2Al + 3CuCl_2=2AlCl_3+3Cu\)

Reaction 11: \(Br_2+CaI_2\)

Bromine (\(Br_2\)) is more reactive than iodine (\(I_2\)). The reaction is \(Br_2+CaI_2 = CaBr_2+I_2\)

Reaction 12: \(Fe+CuSO_4\)

Iron (\(Fe\)) is more reactive than copper (\(Cu\)). The reaction is \(Fe+CuSO_4 = FeSO_4+Cu\)

Reaction 13: \(Cl_2+MgI_2\)

Chlorine (\(Cl_2\)) is more reactive than iodine (\(I_2\)). The reaction is \(Cl_2+MgI_2=MgCl_2 + I_2\)

Answer:

1. no reaction
2. \(Zn + 2AgNO_3=Zn(NO_3)_2 + 2Ag\)
3. \(Cl_2 + 2KI = 2KCl+I_2\)
4. no reaction
5. \(Fe + Pb(NO_3)_2=Fe(NO_3)_2 + Pb\)
6. no reaction
7. \(2Al+3Pb(NO_3)_2 = 2Al(NO_3)_3+3Pb\)
8. \(Cl_2+2NaI = 2NaCl + I_2\)
9. \(Fe + 2AgC_2H_3O_2=Fe(C_2H_3O_2)_2+2Ag\)
10. \(2Al + 3CuCl_2=2AlCl_3+3Cu\)
11. \(Br_2+CaI_2 = CaBr_2+I_2\)
12. \(Fe+CuSO_4 = FeSO_4+Cu\)
13. \(Cl_2+MgI_2=MgCl_2 + I_2\)