Question

sin x
write the ratio for sin x.
(image of a right triangle with right angle at i, sides: zi = 6, ix = 8, zx = 10)

Explanation:

Step1: Recall sine definition

In a right triangle, $\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$.

Step2: Identify sides for $\angle X$

For $\angle X$, opposite side is $IZ = 6$, hypotenuse is $XZ = 10$.

Step3: Write the ratio

$\sin X = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{6}{10}=\frac{3}{5}$.

Answer:

$\frac{3}{5}$ (or $\frac{6}{10}$)