Question

simplify the fraction completely. if the fraction does not simplify, submit the fraction in its current form. $\frac{21x^{3}}{9x^{4}}$

Explanation:

Step1: Factor out common factors of coefficients

Factor 21 and 9. $21 = 3\times7$ and $9=3\times3$, so $\frac{21x^{3}}{9x^{4}}=\frac{3\times7x^{3}}{3\times3x^{4}}$.

Step2: Use exponent - division rule

According to the rule $\frac{a^{m}}{a^{n}}=a^{m - n}$ ($a
eq0$), for $x$ terms $\frac{x^{3}}{x^{4}}=x^{3-4}=x^{- 1}=\frac{1}{x}$. And cancel out the common factor 3 in the coefficients. We get $\frac{7}{3x}$.

Answer:

$\frac{7}{3x}$