Question

simplify. express your answer using a single exponent.
$(c^{-8})^{-3}$

Explanation:

Step1: Recall exponent rule \((a^m)^n = a^{m\times n}\)

For \((c^{-8})^{-3}\), apply the rule: \(m = -8\), \(n = -3\), so exponent is \(-8\times(-3)\)

Step2: Calculate the product of exponents

\(-8\times(-3)=24\), so \((c^{-8})^{-3}=c^{24}\)

Answer:

\(c^{24}\)