Question

simplify.

\\4w^2 \cdot 4y^6 \cdot 4y^{-4} v^7 v w^{-3}\\

use only positive exponents in your answer.

Explanation:

Group coefficients and variables

$$ (4 \cdot 4 \cdot 4) \cdot (w^2 \cdot w^{-3}) \cdot (y^6 \cdot y^{-4}) \cdot (v^7 \cdot v^1) $$

Apply exponent rules to each group

$$
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$$

Convert negative exponents to positive exponents

$$ 64 \cdot w^{-1} \cdot y^2 \cdot v^8 = \frac{64 v^8 y^2}{w} $$

Answer:

$$\frac{64v^8y^2}{w}$$