Question

sigfigcalc3. an empty beaker weighs 12.408g. after some solid is added into this beaker, the total mass becomes 12.708g. what is the mass of the added solid? 0.3 g 0.300 g 25.116 g 0.30 g 25.12 g 25.1 g

Explanation:

Step1: Find the mass difference

The mass of the added solid \(m\) is the difference between the total mass \(m_{total}\) and the mass of the empty beaker \(m_{beaker}\). So \(m = m_{total}-m_{beaker}\).
Substitute \(m_{total}=12.708\ \text{g}\) and \(m_{beaker} = 12.408\ \text{g}\) into the formula: \(m=12.708 - 12.408\).

Step2: Calculate the value

\(12.708-12.408=0.300\ \text{g}\).
For subtraction of decimal - numbers, the result should have the same number of decimal places as the number with the least number of decimal places among the values being subtracted. Here, both \(12.708\) and \(12.408\) have three decimal places.

Answer:

B. \(0.300\ \text{g}\)